38=-16t^2-48t+2

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Solution for 38=-16t^2-48t+2 equation: 



38=-16t^2-48t+2

We move all terms to the left:

38-(-16t^2-48t+2)=0

We get rid of parentheses

16t^2+48t-2+38=0

We add all the numbers together, and all the variables

16t^2+48t+36=0

a = 16; b = 48; c = +36;
Δ = b2-4ac
Δ = 482-4·16·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-48}{32}=-1+1/2$

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